0=-16t^2+10t+26

Solution for 0=-16t^2+10t+26 equation:

0=-16t^2+10t+26

We move all terms to the left:

0-(-16t^2+10t+26)=0

We add all the numbers together, and all the variables

-(-16t^2+10t+26)=0

We get rid of parentheses

16t^2-10t-26=0

a = 16; b = -10; c = -26;
Δ = b2-4ac
Δ = -102-4·16·(-26)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-42}{2*16}=\frac{-32}{32}
=-1
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+42}{2*16}=\frac{52}{32}
=1+5/8
$